Answer

One hundred parts, by weight, of mercury, must be di olved with a gentle heat, in 1000 parts (also by weight) of nitric acid, spec. gr. 1·4; and this solution, at the temperature of about 130° Fahr. must be poured into 830 parts by weight of alcohol, spec. gr. 0·830.— Note. 830 parts of such alcohol, by weight, constitute 1000 by measure; and 1000 parts of such nitric acid, by weight, constitute 740 by measure. Hence, in round numbers, one ounce weight of quicksilver must be di olved in 7 1 ⁄ 2 oz. measures of the above designated nitric acid, and the resulting solution must be poured into 10 oz. measures of the said alcohol.